(x-3)(x^2-4)=0

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Solution for (x-3)(x^2-4)=0 equation:


Simplifying
(x + -3)(x2 + -4) = 0

Reorder the terms:
(-3 + x)(x2 + -4) = 0

Reorder the terms:
(-3 + x)(-4 + x2) = 0

Multiply (-3 + x) * (-4 + x2)
(-3(-4 + x2) + x(-4 + x2)) = 0
((-4 * -3 + x2 * -3) + x(-4 + x2)) = 0
((12 + -3x2) + x(-4 + x2)) = 0
(12 + -3x2 + (-4 * x + x2 * x)) = 0
(12 + -3x2 + (-4x + x3)) = 0

Reorder the terms:
(12 + -4x + -3x2 + x3) = 0
(12 + -4x + -3x2 + x3) = 0

Solving
12 + -4x + -3x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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